A yoyo is allowed to drop freely with a string held fixed in place at the top. Assume that the yoyo is a uniform disk of mass M and radius R. 1) Use Newton's Second Law to find the linear acceleration of the yoyo and the tension in the rope. My answer key says that the answers are 2/3 g for acceleration and (1/3)Mg for tension I have the net force = ma, and net torque = I*alpha. so Net force : mg - T = ma Net torque = I*alpha since this is a cylinder I = (1/2)MR^2 I also know that torque is F*R I have (1/2)M*R^2*alpha = F*R F = (1/2)M*R*alpha Ma = (1/2)M*R*alpha a =(1/2)*alpha *R alpha = a/R so a= (1/2)a This is not true. I know how to find tension. I plugged in the correct value for a into the mg-T=ma. But I can't find the acceleration.