Find Equations for Differentials of 9y^2=x^3+3x^2 at (1,2/3), (-2,2/3), (-3,0)

In summary, the conversation discusses finding the equations relating to differentials on a given curve at specific points. The equations are found to be y'= \frac {x^2+2x}{6y}, 9x-12y-1=0, and y=2/3 for the points (1,\frac{2}{3}), (-2,\frac{2}{3}), and (-3,0) respectively. However, it is noted that the vertical line at x=-3 does not have a slope.
  • #1
erik05
50
0
If anyone could check this answer for me, it would be greatly appreciated.

Find the equations relating the differentials on the curve [tex] 9y^2= x^3 +3x^2 [/tex] at the points [tex] (1,\frac{2}{3}), (-2,\frac{2}{3}), (-3,0) [/tex]

Here's what I got:

[tex] y'= \frac {x^2+2x}{6y} [/tex]

[tex] m @ (1,\frac{2}{3})= \frac {3}{4} [/tex]
equation: 9x-12y-1=0

[tex] m @ (-2,\frac{2}{3})=0 [/tex]
equation: y= 2/3

[tex] m @ (-3,0) [/tex]
does not exist

Thanks in advance.
 
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  • #2
erik05 said:
If anyone could check this answer for me, it would be greatly appreciated.

Find the equations relating the differentials on the curve [tex] 9y^2= x^3 +3x^2 [/tex] at the points [tex] (1,\frac{2}{3}), (-2,\frac{2}{3}), (-3,0) [/tex]

Here's what I got:

[tex] y'= \frac {x^2+2x}{6y} [/tex] <------ CORRECT

[tex] m @ (1,\frac{2}{3})= \frac {3}{4} [/tex]
equation: 9x-12y-1=0 <----- CORRECT

[tex] m @ (-2,\frac{2}{3})=0 [/tex]
equation: y= 2/3 <----- CORRECT

[tex] m @ (-3,0) [/tex]
does not exist <----- Should be the Vertical Line {x = -3}

Thanks in advance.
Everything appears correct except the last item.

~~
 
  • #3
Thanks for the help.
 
There are no specific frequently asked questions about this particular problem, but here are five possible questions that may be asked:

1. What is the differential equation for the given curve?

The differential equation for the given curve is 9y^2=x^3+3x^2.

2. How do you find the derivative of a function?

To find the derivative of a function, you can use the power rule, product rule, quotient rule, or chain rule depending on the function. In this case, the power rule was used to find the derivative of the given function.

3. What are the coordinates of the given points?

The given points are (1,2/3), (-2,2/3), and (-3,0).

4. How do you find the differential equation at a specific point?

To find the differential equation at a specific point, you can use the point-slope form of a line and the derivative of the function at that point. In this problem, the derivative of the function was found at each given point to determine the differential equation.

5. What is the significance of finding the differential equation at specific points?

Finding the differential equation at specific points allows us to understand the behavior of the function at those points. It can also help us make predictions about the function and its derivatives at nearby points.

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