1) A current of .5 A exist on a 60-ohm lamp. Find Potential Difference(adsbygoogle = window.adsbygoogle || []).push({});

Answer - 30 V

2) The sum of currents into a junction equals the sum of the currents out of the junction.

D)convservation of energy

E) Conservation of charge My answer is E

3)Current is a measure of:

D) amount of charge that moves past a point per unit time

E) speed with which a charge moves past a point

My answer is D

4) A 2uF and a 1uF capacitor are connected in a series and a potential difference is applied across the combination. The 2uF capacitor has:

a) twice the charge of the 1uF

b) half the charge of the 1uF

c) twice the potential difference of the 1uF

d) half the potential difference of the 1uF

e) none of the above

C=q/v so I picked A

5) the units of the electric field are

a) J/(C*m)

b) J/C

c) J*C

d) J/m

e) none of these

I know that electric field is N/C, But, I am think that would be the same as J/(C*m) So I say if not A then E

6) The electric field at a distance of 10 cm from an isolated point charge of (2x10^9 C) is: I cant even find a formula for this one.

7) A car battery is rated at 80 A * h is a unit of:

a) power

b) energy

c) current

d) charge

e) force

My ansswer is A) power

8) The capacitance of a parrallel-plate capacitor can be increase by:

A) increasing the charge

b) decreasing the charge

c) increasing the plate separation

d) decreasing the plate separation

e) decreasing the plate area

C=E A/d So I assume that if you decrease distance you will in crease capacitance. So d) decreast the plate separation.

Thanks

Nautica

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# Homework Help: Answer check

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