-log5(cos(x)) = -1/2
How many answers are there in the interval [0,2pi)
The Attempt at a Solution
5^-1/2 = cos(x)
1/sq rt 5 = cos(x)
sq rt 5/5 = cos(x)
0.447 = cos(x)
x = 63.43
Basically, I have no clue how to find the number of answers in the interval ; (
I think I have missed this question or a variation of it like 12 times now ; /.. Things I have tried that work sometimes ( good guessing... Unfortunately when I tried applying it to a new problem it didnt work) is seeing how many times 63 went into 180, simply assuming its two as 180-63, then seeing how many times it went into 360 but this was not even an answer choice so idk...
If the answer is 4 I will have to cry.