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Anti-log problem help

  1. Feb 22, 2005 #1
    log(35-x^3)/log(5-x)=3

    I can't get it.....

    What I did was: 1000=(35-x^3)/(5-x)
     
  2. jcsd
  3. Feb 22, 2005 #2
    Putting this in a better grouping you get [tex] 3log(5-x)=log(35-x^{3}) [/tex]

    Take the anti-log of both sides from there.
     
    Last edited: Feb 22, 2005
  4. Feb 22, 2005 #3

    Integral

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    [tex] \frac {\ln x} {\ln y} \neq \ln ( \frac x y) [/tex] so what you have is not correct.


    Your first step should be

    [tex] \ln (35- x ^3) = 3 \ln (5-x) [/tex]

    Can you proceed from there?
     
  5. Feb 22, 2005 #4
    i got it thank you.......
     
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