# Anti-log problem help

1. Feb 22, 2005

### thomasrules

log(35-x^3)/log(5-x)=3

I can't get it.....

What I did was: 1000=(35-x^3)/(5-x)

2. Feb 22, 2005

### Jameson

Putting this in a better grouping you get $$3log(5-x)=log(35-x^{3})$$

Take the anti-log of both sides from there.

Last edited: Feb 22, 2005
3. Feb 22, 2005

### Integral

Staff Emeritus
$$\frac {\ln x} {\ln y} \neq \ln ( \frac x y)$$ so what you have is not correct.

Your first step should be

$$\ln (35- x ^3) = 3 \ln (5-x)$$

Can you proceed from there?

4. Feb 22, 2005

### thomasrules

i got it thank you.......

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