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Introductory Physics Homework Help
Anti-reflective lenses and interference
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[QUOTE="joshwarner, post: 6636742, member: 701112"] To remove the reflection on the glasses, the additional layer creates a new reflection of the light in order for the two waves reflected to interfere destructively when having a phase difference of an odd multiple of π. So using the distance traveled by the two waves, we get, at normal incidence, with w being the width of the coating layer : (k+1/2)λ=2nw+λ/2. However I still don't see how this explains the reflectance being worth 0 for λ=500nm. [/QUOTE]
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Introductory Physics Homework Help
Anti-reflective lenses and interference
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