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Antiderivate arccos

  1. Aug 20, 2008 #1
    Hello, can somebody here tell me how to solwe the antiderivate of

    arcsin(x^0,5)/(x^0,5)

    I know the answer but not the solution..
     
  2. jcsd
  3. Aug 20, 2008 #2
    let [tex] u = x^{.5} [/tex]
     
  4. Aug 20, 2008 #3

    nicksauce

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    First make a substiution, so that you are integrating arcsin(y)dy. Then integrate by parts u = arcsin(y) du = sqrt(1-y^2)dy dv=dy v =y. The resulting integral of vdu shouldn't be too hard to solve.
     
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