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## Homework Statement

Find the antiderivative: ∫[(3x+1)/cos^2(3x^2+2x)]dx

## Homework Equations

## The Attempt at a Solution

I attempted to use "u substitution" but got stuck towards the end:

u=3x^2+2x

du=6x+2dx

=2(3x+1)dx

du/2=(3x+1)dx

After my substitutions it looks like this:

∫(du)/2cos^2(u) = 1/2∫(du)/cos^2(u)

What do I do with the cos^2?

Thanks for any help that can be given