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meee
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Antiderivative of this? - kinematics
a kinematics question
v = 1 + e^x
find x in terms of t given that x = 0 when t = 0
what i did:
dx/dt = 1 + e^x
dt/dx = 1/ (1+ e^x)
so t = the antiderivative of 1/(1+ e^x)
i tried and i kinda did this...
loge(1 + e^x)/e^x + cbut it doesn't seem right
a kinematics question
v = 1 + e^x
find x in terms of t given that x = 0 when t = 0
what i did:
dx/dt = 1 + e^x
dt/dx = 1/ (1+ e^x)
so t = the antiderivative of 1/(1+ e^x)
i tried and i kinda did this...
loge(1 + e^x)/e^x + cbut it doesn't seem right
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