Antiderivative trig function

  • Thread starter cemar.
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  • #1
cemar.
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Hey guys!
So i have to find the antiderivative of
(1-cos(t/6))^3 * sin(t/6)
I have tried a bunch of different ways like by parts, trig substitution, identities, u-substitution then developing it, etc. but i just can't get it!
Can some one just tell me the proper method to use after that I am sure i can figure it out.
thanks!
 

Answers and Replies

  • #2
Dick
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You must not have tried u substitution very hard. Try u=(1-cos(t/6)).
 
  • #3
Defennder
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It should be doable. Or so says Wolfram's online integrator. I tried it out and managed to reduce it to a doable trigo form. You only need use integration by parts and then replace all those trig terms which are of power 2 and 3 with power 1 terms by means of some trigo formulae.
 
  • #4
Dick
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It should be doable. Or so says Wolfram's online integrator. I tried it out and managed to reduce it to a doable trigo form. You only need use integration by parts and then replace all those trig terms which are of power 2 and 3 with power 1 terms by means of some trigo formulae.

I don't see why you are working so hard on it. There's a much simpler way.
 
  • #5
Defennder
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You're right, I just didn't see it before you posted.
 

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