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given:

y=f(x)

f^{|}(1)=4

g(x)=f(x^{2})

find g^{|}(-1)

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i know that g(-1)=g(1) because g is a squared function of x, but thats about it,

can i say-

g^{|}(x)=[f(x^{2})]^{|}=f^{|}(x^{2})*(2x)

and because x=-1, and -1^{2}=1, and i know f^{|}(1)=4

so

g^{|}(-1)=-8

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# Homework Help: Any ideas?

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