1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Any ideas ?

  1. Jan 22, 2009 #1
    Any ideas ??

    1. The problem statement, all variables and given/known data

    divide 6705 in the (ratio square r00t sign-2 : square root sign-8).

    3. The attempt at a solution

    I don't know where to begin.
  2. jcsd
  3. Jan 22, 2009 #2
    Re: Any ideas ??

    I have no idea what you are asking.
  4. Jan 22, 2009 #3
    Re: Any ideas ??

    Basically it has to do with ratios.

    I am asking how would you divide £6705 in the ratio 2:8.

    But both the 2 and 8 have a square root sign each, but i cannot put the sign because my keyboard hasn't got a key with a sign on it.

    It doesn't really make sense to me and thats why i am asking you guys to see if any one can help me.

  5. Jan 22, 2009 #4
    Re: Any ideas ??

    Yes but those are still just numbers, you are trying to proportion out 6705, you are told relative weights, so what would the equation be?

    Let's try a simple problem let's say it WAS just 2:8, how would you do it?
  6. Jan 22, 2009 #5
    Re: Any ideas ??

    Adding 2 and 8 together and then divide the total amount by the amount i got after i added.

    That would give me the ratio in each unit.
  7. Jan 22, 2009 #6
    Re: Any ideas ??

    Right so tell me the final answer, if I told you the relative weights are 2 and 8, how much would go each "bucket"
  8. Jan 22, 2009 #7
    Re: Any ideas ??


    6705 / 10=670.5

    670.5 is the amount of each unit in the ratio, If i multiply 670.5 by 2 i get 1341 and 670.5 multiply by 8 i get 5364.

    Thats all good but my only problem lies with the square root sign if you know what i mean.

    Attached Files:

  9. Jan 22, 2009 #8
    Re: Any ideas ??

    The square root should not matter.

    Look at what you did, you had a:b

    So you said amounts in "one" unit is 6705/(a+b).

    Now the amount in the "first bucket" is a*6705/(a+b) and in the "second bucket" it's b*6705/(a+b).

    In the example we just worked, a = 2, b = 8. In your problem, [tex] a = \sqrt{2}, b = \sqrt{8} [/tex]

    Note also that [tex] \sqrt{8} = 2 \sqrt{2} [/tex] so you can simplify your calculations a little bit.
  10. Jan 22, 2009 #9
    Re: Any ideas ??

    So when i get the solution, should the square root sign still be there ?
  11. Jan 22, 2009 #10
    Re: Any ideas ??

    Nope, show me your work using what I told you.
  12. Jan 22, 2009 #11
    Re: Any ideas ??

    i got 2236.3 for A using the formula you gave me.

    I am a little bit confused somewhere.

    Is there any chance you could do part A and show me what you mean.
  13. Jan 22, 2009 #12
    Re: Any ideas ??

    Go ahead and show you work like I said in the previous post.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?