we know that [tex]\delta(xa)=(1/a)\delta(x) [/tex] if the dirac,s delta satisfies this then given the function H(ax) with H the Heaviside step function what relationship is there between H(ax) and H(x) with(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \frac{dH}{dx}=\delta(x) [/tex]

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# Aobut delta and Heaviside function...

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