Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Aobut delta and Heaviside function

  1. Jul 15, 2005 #1
    we know that [tex]\delta(xa)=(1/a)\delta(x) [/tex] if the dirac,s delta satisfies this then given the function H(ax) with H the Heaviside step function what relationship is there between H(ax) and H(x) with

    [tex] \frac{dH}{dx}=\delta(x) [/tex]
  2. jcsd
  3. Jul 15, 2005 #2
    H(ax) = H(x).
  4. Jul 15, 2005 #3
    [tex] (H(ax))' = a H'(ax) = a \delta (ax) =\delta (x) = H'(x) [/tex]
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook