- #1
eljose
- 492
- 0
we know that [tex]\delta(xa)=(1/a)\delta(x) [/tex] if the dirac,s delta satisfies this then given the function H(ax) with H the Heaviside step function what relationship is there between H(ax) and H(x) with
[tex] \frac{dH}{dx}=\delta(x) [/tex]
[tex] \frac{dH}{dx}=\delta(x) [/tex]