# Ap calc AB problems

1. May 1, 2005

### kreil

I have been having trouble with this kind of problem lately and I need to know if what I have done here is right (calculator problem but I have not evaluated anything yet):

Let R be the region bounded by the y-axis and the graphs of

$$y=\frac{x^3}{1+x^2}$$ and

$$y=4-2x$$

a) Find the area of R
b) Find the volume of the solid generated when R is revolved about the x-axis
c)The region R is the base of a solid. For this solid, each cross section parallel to the x-axis is a square. Find the volume of this solid.

a)
a=point of intersection of the two graphs

$$\int_0^a(4-2x-\frac{x^3}{1+x^2})dx$$

b)
$${\pi}\int_0^a(4-2x)^2-(\frac{x^3}{1+x^2})^2dx$$

c)
$$\pi \int_0^a(4-2x-\frac{x^3}{1+x^2})^2dx$$

Last edited: May 1, 2005
2. May 1, 2005

### UrbanXrisis

there shouldn't be a $\pi$ in front of the integral on letter c.

everything else is fine

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