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If dy/dx = 2y^2 and if y=-1 when x=1
then when x=2, y=?
I have no idea how to even start this probelm, i never seen this on any previous practice tests
i thought about using the equation y+1 = dy/dx (x-1), but thats probaly wrong and not going to help...
then when x=2, y=?
I have no idea how to even start this probelm, i never seen this on any previous practice tests
i thought about using the equation y+1 = dy/dx (x-1), but thats probaly wrong and not going to help...