# AP Calculus BC: Differentiability and continuity

You are defining a function h whose value h(x) is equal to -1 for every real number x. Since h(x) = -1 for every x, then surely h(x) = h(2-x).

Ohh so if i'm not mistaken, we are simply trying to find a possible function that doesn't satisfy 1 &3 but could possibly satisfy h(x)=h(2-x)

Thank you so much for your time and help! :)

More specifically, you have already proven that if a function is differentiable and h(x) =h(2-x) then condition 2 is automatically satisfied. But now you have provided a function that is differentiable and h(x) =h(2-x), but violates condition 1 and 3. So you can only conclude condition 2 must be satisfied.