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For all real numbers x, f is a differentiable function such that f(-x)=f(x). Let f(p)=1 and f'(p)=5 for some p>0.

a) Find f'(-p).

b) Find f'(0).

c) If line 1 and line 2 are lines tangent to the graph of f at (-p,1) and (p,1), respectively, and if line 1 and line 2 intersect at point Q, find the x- and y-coordinates of Q in terms of p.

I'm sure this problem is not incredibly hard but I'm very much confused. Please help me get started on it.

Ryan