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AP Calculus

  1. Oct 11, 2007 #1
    1. The problem statement, all variables and given/known data

    A particle moves along the y-axis with position defined by y(t) = -1/2cos(t^2) + 7/2 t≥ 0

    a. find(2)
    b. in which direction is the particle moving at time t=1.5?
    c. find the acceleration of the particle at time t=1.5 Is the velocity of the particle increasing at t=1.5 Why or why not?
    d. Find the total distance traveled by the particle from t=0 to t=2

    2. Relevant equations

    related rates, derivatives


    3. The attempt at a solution

    I tried to solve the problem but I dont know if its right in some parts, so can somebody help me to see if there is something wrong, thanks

    for part a I got y(2) = 3.83

    for part b v(t) = tsint^2
    v(1.5) = 1.5sin(1.5^2)
    = 1.167

    for part c: a(t) = sin(t^2) + 2(t^2)cos(t^2)
    a(1.5) = -2.04
    No, because the acceleration and the velocity doesn't have the same sign


    for part d
    of t=0 ---> t=2
    y(0) = 3
    y(1) = 3.2
    t(2) 3.8

    distance = (3.8 - 3) = 0.8
     
  2. jcsd
  3. Oct 11, 2007 #2

    ptr

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    The part letter b asks only for a direction, so the answer should either be positive or negative. In part letter d, you would do better to identify the roots of the displacement equation and find the displacements in each direction (the intervals separated by the zeroes), and then add the absolute value of the results up. This is because the particle is travelling in one dimension and the question asks for distance and not displacement.
     
  4. Oct 11, 2007 #3
    edit
     
    Last edited: Oct 11, 2007
  5. Oct 11, 2007 #4
    so for d can I use the distance formula?
     
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