Apatite homework help

  • Thread starter chawki
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Homework Statement


Apatite (Ca5(PO4)3F) is used to manufacture fertilizer.

Homework Equations


How many kilograms of pure phosphorus (P) is included in 1150 kg of apatite?



The Attempt at a Solution


How we solve this, tell me only first step...
we can't even use the composition percentage law :grumpy:
 

Answers and Replies

  • #2
chemisttree
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Start with the forumla weight of apatite. Convert to moles.

Can you take it from there?
 
  • #3
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can you please tell me how to find the formula weight?
i have learnt chemistry ages ago..and it was in french..

maybe you meant the molar mass ? if it's that, then it is 504.31g/mol
504.31 = 1150000/n
n= 1150000/504.31
n= 2280.34mol
 
Last edited:
  • #4
chemisttree
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Right, that's how many moles of apatite. How many moles of phosphorous per mole of apatite?
 
  • #5
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That's where i'm stuck
 
  • #6
chemisttree
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Just look at the empirical formula. You do this part by inspection... nothing to calculate.
 
  • #7
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1mole
 
  • #8
chemisttree
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So if you were given 1 mole of Ca5(PO4)3F, you would get only one mole of P out of it?
 
  • #9
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i'm not sure, i'm confused
 
  • #10
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mp/30.97 = 1150000/504.31
mp= 7062.22g
 
  • #11
chemisttree
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AxBy gives you x moles of A and y moles of B per mole of AxBy.

How about the moles of P in one mole of Ca5(PO4)3F?
 
  • #12
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Three
 
  • #13
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So if you were given 1 mole of Ca5(PO4)3F, you would get only one mole of P out of it?

Not necessarly i think
 
  • #14
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mp/30.97 = 1150000/504.31
mp= 7062.22g

70622.23
 
  • #15
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Please tell me if i'm right
 
  • #16
Borek
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No. You have still ignored fact that there are three moles of P per apatite molecule.
 
  • #17
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mp/3*30.97 = 1150000/504.31
mp= 211866.709g
mp=211.866Kg
 
  • #18
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Please reply to my posts!
 
  • #19
Borek
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We are not your private tutorial service, aren't we?

Watch significant figures.
 
  • #20
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No, You are not. and i want to say that i appreciate having time for posting and replying.
God bless you all.
 

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