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Apparent (clearly false) contradiction - Kepler's Third Law
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[QUOTE="Brad, post: 5961933, member: 642797"] [h2]Homework Statement [/h2] When considering a satellite in geosynchronous orbit, its speed is zero across (relative to) Earth's surface. From Kepler's third Law: T[SUP]2[/SUP]=(4π[SUP]2[/SUP]r[SUP]3[/SUP])/(GM), we can derive that v[SUP]2[/SUP]=GM/r This would tell us that as the radius of a satellite to Earth's centre increases, its velocity [U]decreases[/U] by a squared amount. My Physics Class realized that, for the period of Earth and consequently the satellite to be constant, an increased radius from Earth's centre would require the satellite to travel at a [U]faster[/U] velocity. We could not explain this apparent anomaly and were clearly not accounting for some crucial factor. Any help at explaining where we are wrong would be appreciated. Thanks :) [h2]Homework Equations[/h2][h2]The Attempt at a Solution[/h2] [/QUOTE]
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Introductory Physics Homework Help
Apparent (clearly false) contradiction - Kepler's Third Law
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