A fish is 80 cm below the surface of a pond. What is the apparent depth (in cm) when viewed from a position almost directly above the fish? (For water, n = 1.33.)
Snell's law: [tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
The Attempt at a Solution
So far I have found the angle of refraction in the water using Snell's law. Since they are asking for "a position almost directly above the fish", I took [tex]\theta_1 = 90[/tex].
[tex]1= 1.33 sin \theta_2[/tex]
[tex]\theta_2 = 48.75[/tex]
But I what else can I do?? I'm really stuck! I need to find the difference between he apparent and the real depth x, 80-x=apparent length. But how? Here's a diagram which shows a similar situation:
The correct answer is 60 cm.