1. The problem statement, all variables and given/known data A fish is 80 cm below the surface of a pond. What is the apparent depth (in cm) when viewed from a position almost directly above the fish? (For water, n = 1.33.) 2. Relevant equations Snell's law: [tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex] 3. The attempt at a solution So far I have found the angle of refraction in the water using Snell's law. Since they are asking for "a position almost directly above the fish", I took [tex]\theta_1 = 90[/tex]. [tex]1= 1.33 sin \theta_2[/tex] [tex]\theta_2 = 48.75[/tex] But I what else can I do?? I'm really stuck! I need to find the difference between he apparent and the real depth x, 80-x=apparent length. But how? Here's a diagram which shows a similar situation: The correct answer is 60 cm.