# Homework Help: Apparent Weight Elevator Speed

1. Oct 5, 2008

### shimizua

1. The problem statement, all variables and given/known data
Referring to the problem above, if the elevator's descending speed is measured at 10 m/s at a given point, but its speed is decreasing by 2.5 m/s2, what is her apparent weight?.
And the problem above it was this
A 58.0 kg girl weighs herself by standing on a scale in an elevator. What is her apparent weight when the elevator is descending at a constant speed of 10 m/s?

2. Relevant equations
So i was able to find the answer to the first question which was 568N and found it by doing her mass times the gravity. but i have no i idea of how to do it when the speed it decreasing.

3. The attempt at a solution
i tried doing her mass times her acceleration which was 10m/s and that was wrong and so i then tried doing her mass time her deceleration of 2.5m/s/s and that was wrong as well. if you could just help with an equation that should be good enough. thanks

2. Oct 6, 2008

### Kurdt

Staff Emeritus
Her apparent weight will be the weight due to gravity plus the force exerted on her by the lift.

Last edited: Oct 6, 2008
3. Oct 6, 2008

### shimizua

ok so i would use my initial number of 568N and add that to what? her mass times the deceleration?
cool so i put that in and it does work, thanks man

4. Oct 6, 2008

### HallsofIvy

Yes, force = mass times acceleration. If the elevator is accelerating upward, then you would feel g+ mass * acceleration. If the elevator is accelerating downward, then you would feel g- mass*acceleration.