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Apparent weight

  1. Jul 16, 2004 #1
    An object hanging in the air causes a scale to read 0.0451kg. When the object was submerged in water, the scale is balanced at 0.0370. I found the object of the weight in air to be 0.442N. The question is to find the apparent weight when submerged in water. How do I find the volume to find the apparent weight. So far, I have 0.442-(1000kg/m^3)(9.8m/s^2)(V)=W. What's the volume?
  2. jcsd
  3. Jul 16, 2004 #2

    Doc Al

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    Staff: Mentor

    I presume that by "apparent weight" is meant what the scale reads when the object is submerged. You measured the apparent weight directly, so what are you calculating?
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