Another one of my pesky conservation of energy and momentum problems. A 0.74-kg apple is tossed straight up from 1.3m above the ground with and initial speed of 7.3m/s. When it has traveled 1.5m upward it is struck by a 0.15-kg arrow which sticks in the apple. Just before the impact the arrow was traveling at a speed of 30m/s at and upward angle of 57° from the horizontal. a) What speed did the apple have just before the arrow struck it? b) What was the speed and the direction of the apple-arrow immediately after impact? c) How far from a spot directly below the apple's initial location does the apple-arrow hit the ground? For part (a) I got v = 4.9 m/s. After that, I'm not sure what to do.