The table (below) shows the force needed to push a 10-kg box up a ramp as the angles increase. From the trend in the table, what is the applied force needed if the angle of the ramp increases to 50 degrees?
Applied Force (N) ; Ramp Angle (Degrees)
19N ; 10 degrees
30N ; 20 degrees
40N ; 30 degrees
49N ; 40 degrees
applied force = mg sin(degree of angle)
The Attempt at a Solution
I honestly don't know about this, and I'm not really looking for the answer to the problem, just the "how-to". I tried, with the equation above, to see if it worked for the 19N ; 10 degrees (in the table). My work looked like:
applied force = (10kg)(9.81)sin(10) = 17.0348....
This obviously isn't the 19N that I was supposed to get. I can't find any decent explanations for this problem, and would appreciate any help.