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Applied Maths Mechanics (AS M1)

  1. Oct 29, 2005 #1
    Hi everybody.
    I have started with the M1 Mechanics Course this term and my teacher gave me some exam questions to do over the half term break but now I am stuck on one of the questions and I hope someone here will be able to help me.

    So here is the question:
    (read l as lamda and m as mue)

    A force F2 = (l i + m j ) acts on a particle.

    Show that 2l - m + 1 = 0.
    Given that the direction of F2 is parallel to j

    I have started to think about this problem and came up with

    (l + m) = (0+1) x constant
    l = 0 x constant.
    m = 1 x constant.

    But this does not really help me at all. and i can't think about much else to do so I am very happy over every hint you can offer me.

    Thanks in advance.
    Ancient.
     
  2. jcsd
  3. Oct 29, 2005 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Perhaps I don't understand the question. If F2 is li+ mj, is there an F1?
    "Given that the direction of F2 is parallel to j" it follows that l must be 0. It is NOT necessary that m= 1. Is there another force with i component 1- m?
     
  4. Oct 29, 2005 #3
    Hi and thanks for helping.

    There is another Force F1 = (2i + 3j) but I do not think that it is relevant for this part of the question.
     
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