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I have a few questions on applied maxima and minima

1. A company gives you 675 sq. ft of cardboard to construct a rectangular carton with the largest volume. If the carton is to have a square base and an open top, what dimensions would you use?

My Thought Process:

Volume = length * width * height

= x*x* (675- 2x)

I know how to find the maximum volume, but am not sure about the actual equation. If it has a square base, then shouldn't it be x*x *( 675 - 2x)

Any help is greatly appreciated

Thanks

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# Applied Maxima and Minima Problems

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