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I was wondering, with a singly ionised He atom, can we apply the Bohr model, eg E = 13.6eV/n^2, to find the energy of the excited states? How would i go about that?

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- Thread starter MaximumTaco
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- #1

- 45

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I was wondering, with a singly ionised He atom, can we apply the Bohr model, eg E = 13.6eV/n^2, to find the energy of the excited states? How would i go about that?

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[tex]1s^1[/tex] ground state:

[tex]E_{1s^1}(Z,n) = \frac{(13.6ev)Z_n^2}{n^2}[/tex]

[tex]E_{1s^1}(Z,n) = \frac{\alpha^2 M_e c^2 Z_n^2}{2qn^2} = \frac{M_e}{2q} \left( \frac{\alpha c Z_n}{n} \right)^2[/tex]

[tex]E_{1s^1}(Z,n) = \frac{M_e}{2q} \left( \frac{\alpha c Z_n}{n} \right)^2[/tex]

This equation seems to work for ALL beta [tex]1s^1[/tex] states.

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