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Introductory Physics Homework Help
Applying Conservation of Momentum along the Y axis
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[QUOTE="Better WOrld, post: 5257863, member: 562898"] Thanks for responding Sir. Sir, I can't understand how to apply it though (ie I can't form the equations properly). Sir, the initial Momentum in the horizontal direction is ##0##. Thus the Initial Momentum along the Y axis is $$(M_{earth}\times 0)+(M\times 0)+(m\times 0)$$ However, for the final momentum along the Y axis, I get $$(M_{earth}\times 0)+(M\times 0)+(m\times -v\hat{i})$$ which is clearly not equal to initial Momentum. I made the assumption that the Earth has no velocity either initially or finally since till date I've always been taught (perhaps incorrectly) that we assume the Earth to be at absolute rest. In any case, when the block ##just ## ##reaches## the bottom of the earth, I assumed that the block had not yet collided with the earth. Hence, I fail to see what could impart any velocity to the Earth. Could you please correct my mistake Sir?Lastly, could you please explain how to apply the Conservation of Mechanical Energy assuming the System is ##Wedge+Block +Earth##? The equation I get (assuming the Earth does not move) is as follows: $$\large{PE_{earth}+mgH+Mg\dfrac{h}{3}=\dfrac{1}{2}MV_W^2+\dfrac{1}{2}mv_{block,earth}^2+PE_{earth}}$$ where U=0 at the Earth's surface. [/QUOTE]
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Introductory Physics Homework Help
Applying Conservation of Momentum along the Y axis
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