- #1

Kennedy111

- 27

- 0

## Homework Statement

What is the distance between two charges of -5.00 C each if the force of electrostatic repulsion acting on them is 4.00 x 10^3 N?

q1 = -5.00 C

q2 = -5.00 C

Fe = 4.00 x 10^3

k = 8.99 x 10^9 Nm^2/C^2

## Homework Equations

Fe = kq1q2/r^2

## The Attempt at a Solution

I rearranged the equation above and got:

r = (sqrt) kq1q2/Fe

r = (sqrt) (8.99 x 10^9 Nm^2/C^2)(5.00 C)(5.00 C) / (4.00 x 10^3 N)

= 7495.832175 m

To three significant digits my answer would be 7.50 x 10^ 3 m