Applying Torque at an angle

Homework Statement

A Force F = 76.0N is applied to a box with dimensions y = 2.69m, x = 1.04m. The force is applied at an angle theta with respect to the horizontal as shown. For theata = 24.0 deg, calculate the magnitude of the torque produced by F about the point O.

Homework Equations

T=r(Fperpendicular)
Fperpendicular = Fsin(theta)

The Attempt at a Solution

I did pythagorean theorem (a2 + b2 = c2) to find the diagonal (r) at 2.88404m
I then found Fperpendicular by using Fperpendicular = 76Nsin(24deg) = -68.823956N . I then multiplied this by the r I found earlier to find the magnitude of Torque at -198.4911991N. Somehow this is wrong and I don't know how else to do it.

Last edited:

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tiny-tim
Homework Helper
Welcome to PF

Hi Kamikaze! Welcome to PF

(have a theta: θ and a degree: ° and try using the X2 tag just above the Reply box )
I then found Fperpendicular by using Fperpendicular = 76Nsin(24deg)
wrong angle!

useful tip: always draw your diagrams fully … if you'd put in the extra lines, you'd see it isn't θ.