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Approximate the integral int (1 - cos x)/x dx using Taylor expansion

  1. Sep 20, 2005 #1
    I am supposed to find an approximation of this integral evaluated between the limits 0 and 1 using a taylor expansion for cos x:

    [tex]\int \frac{1 - cos x}{x}dx[/tex]

    and given

    [tex]cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!}...[/tex]

    i should get a simple series similar to this for [tex]\frac{1 - cos x}{x}[/tex] and be able to simply integrate each term of the series and evaluate the integral for an approx. how do i find this series?
  2. jcsd
  3. Sep 20, 2005 #2
    Just sub in the series into the integral instaed of cos (x). The 1's will cancel and the x at the bottom will decrease the power of each x on top by 1. Then integrate.
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