1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Approximate the integral int (1 - cos x)/x dx using Taylor expansion

  1. Sep 20, 2005 #1
    I am supposed to find an approximation of this integral evaluated between the limits 0 and 1 using a taylor expansion for cos x:

    [tex]\int \frac{1 - cos x}{x}dx[/tex]

    and given

    [tex]cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!}...[/tex]

    i should get a simple series similar to this for [tex]\frac{1 - cos x}{x}[/tex] and be able to simply integrate each term of the series and evaluate the integral for an approx. how do i find this series?
     
  2. jcsd
  3. Sep 20, 2005 #2
    Just sub in the series into the integral instaed of cos (x). The 1's will cancel and the x at the bottom will decrease the power of each x on top by 1. Then integrate.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Approximate the integral int (1 - cos x)/x dx using Taylor expansion
  1. Integral of 1/(1+x^2) (Replies: 3)

Loading...