Arc Length Integral Question

  • Thread starter v0id19
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  • #1
v0id19
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Homework Statement


Find the arc length of the equation [tex]y^2=4(x+4)^3[/tex] from [tex]x=0[/tex] to [tex]x=2[/tex]

Homework Equations


[tex]L=\int_{a}^{b}\sqrt{1+f'(x)}dx[/tex]


The Attempt at a Solution


[tex]L=\int_{0}^{2}\sqrt{1+9(x+4)}dx[/tex]
which simplifies in to
[tex]L=\int_{0}^{2}\sqrt{9x+37}dx[/tex]
and i'm stuck there--how should i try to integrate that?
 

Answers and Replies

  • #2
Dick
Science Advisor
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Substitute u=9x+37?
 
  • #3
v0id19
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oh. wow. thanks.
now i feel kinda dumb lol i was making it more complicated than i had to, trying trig sub and stuff.
so [tex]dx=\frac{du}{9}[/tex].
sweet.
 

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