# Arc length integral

## Homework Statement

ok, the original prob is : find the length of the curve of y=ln(1-x^2) x between 0, 1/2.

## The Attempt at a Solution

ive made it this far: my integral is -1 + 2/1-x^2..............ok so i decompose the second part but in doing so i get a negative to make it -(x+1)(x-1) but i don't know what happens to that negative because the solution manual says the integral is .......-1+ 1/x+1 -1/x-1 dx i don't get the signs. please help!

if we are woking with single variable functions, y=f(x) like here then the arc length from a to be of a curve is:

$$L=\int_a^b\sqrt{1+[f'(x)]^2}dx$$

yes....like i said ive already worked that part....im toward the end of the problem i just don't get the signs

yes....like i said ive already worked that part....im toward the end of the problem i just don't get the signs

Well, since you have shown almost no work(step by step) it is hard to tell where you have missed, or what you are doing wrong.

got it...nvm..thanks

got it...nvm..thanks