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## Homework Statement

y = (2/3) * (x^2 - 1) ^ (3/2) 1 <= x <= 3

Length = ?

## Homework Equations

L = [tex]\int\sqrt{1 + (dy/dx)^2} dx[/tex]

## The Attempt at a Solution

dy/dx y = (2/3) * (x^2 - 1) ^ (3/2) =

2x * sqrt(x - 1)

Any ideas for a proper substitution? The answer on wolfram seems ridiculous.

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