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Arc Length

  1. Sep 23, 2006 #1
    If [tex] y = \frac{x^{3}}{6} + \frac{1}{2x}\ [/tex] and [tex] \frac{1}{2}\leq x\leq 1 [/tex]. Find the arc length.

    So [tex] \frac{dy}{dx} = \frac{x^{2}}{2} - \frac{1}{2x^{2}} [/tex]. So I got [tex] \frac{1}{2} \int^{1}_{\frac{1}{2}} \sqrt{2+x^{4} + x^{-4}} dx [/tex]. How would you evaulate this?

    Last edited: Sep 23, 2006
  2. jcsd
  3. Sep 23, 2006 #2
    nvm got it. just a perfect square
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