# Arc Length

1. Sep 23, 2006

### courtrigrad

If $$y = \frac{x^{3}}{6} + \frac{1}{2x}\$$ and $$\frac{1}{2}\leq x\leq 1$$. Find the arc length.

So $$\frac{dy}{dx} = \frac{x^{2}}{2} - \frac{1}{2x^{2}}$$. So I got $$\frac{1}{2} \int^{1}_{\frac{1}{2}} \sqrt{2+x^{4} + x^{-4}} dx$$. How would you evaulate this?

Thanks

Last edited: Sep 23, 2006
2. Sep 23, 2006

### courtrigrad

nvm got it. just a perfect square

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