1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Arc Length

  1. Sep 23, 2006 #1
    If [tex] y = \frac{x^{3}}{6} + \frac{1}{2x}\ [/tex] and [tex] \frac{1}{2}\leq x\leq 1 [/tex]. Find the arc length.

    So [tex] \frac{dy}{dx} = \frac{x^{2}}{2} - \frac{1}{2x^{2}} [/tex]. So I got [tex] \frac{1}{2} \int^{1}_{\frac{1}{2}} \sqrt{2+x^{4} + x^{-4}} dx [/tex]. How would you evaulate this?

    Last edited: Sep 23, 2006
  2. jcsd
  3. Sep 23, 2006 #2
    nvm got it. just a perfect square
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook