Since acos(x) = ∫-1/√(1-x^2), and asin(x) = ∫1/√(1-x^2), won't ∫-1/√(1-x^2) = acos(x) = -1*asin(x)?
arcsin x + arccos x = pi/2
so I think what you have is wrong, check again.
I doublechecked, but I still can't find my error..
Nikitin, is there any chance that you are forgetting the constant of integration?
oops, yeh, true :p
sorry, I had a brainfart due to 3 weeks of exams
Separate names with a comma.