What happens if you have to take the arccos of a number greater than 1 or less than -1.(adsbygoogle = window.adsbygoogle || []).push({});

I know from a right triangle if you have:

[ tex ]\Theta[ /tex ]=arccos(x)

if you use x as the adjacent side, 1 as the hypotenuse and [ tex ]\sqrt{1-x^2}[ /tex ] as the opposite.

Is that where the negative sign start?

I have an equation that has numbers from -1.01 to 1.01 as inputs "x". The output runs from 0 to 180 without the numbers 180 to 359 or any negative numbers.

Where do I find the negative or the higher angles?

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# Arccos(x) where x>1 or x<-1

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