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Archimedes law

  1. Mar 22, 2012 #1
    Why isn't the influence of air pressure assimilated in Archimedes law?

    If an obect is more dense than the fluid, it wil sink. That is clear, but suppose I could lower down de air pressue, so less force that tends to push the object tot the surface. Is there any situation possible of adjusting the air pressure to get an object just floating? Or is the influence of the air pressure in incompressible fluids not great, so change in pressure wouldn't be noticed very much?

    But , think of it as an theoretical question.

    thank in advance
  2. jcsd
  3. Mar 22, 2012 #2


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    The key factors are the density of the fluid and the object, with gravity the controlling force. Air pressure plays no role.
  4. Mar 23, 2012 #3
    The reason is that it can be neglected, is that correct?
  5. Mar 23, 2012 #4


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    Your question is confusing. The air pressure is the same on both the object and the water.
  6. Mar 23, 2012 #5

    jim hardy

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    An object immersed in air experiences bouyancy.

    I think it IS accounted for in Archimedes' law.

    You answered your question in OP.
    Have more faith in yourself !

    In slide rule days the effect was too small to warrant consideration, but with today's umpteen-digit calculators i'm sure it could be included. Try it and see how many digits out it shows up.

    From wiki,
    Last edited: Mar 23, 2012
  7. Mar 23, 2012 #6
  8. Mar 29, 2012 #7
    I re-analysed it and atmospherical pressure cannot influence the dyncamic behaviour of a particle that is submerged complete. So there Archimedes law cannot account for it at all.

    Correct, in general air pressure will influence the behaviour of any particle in contact with the air pressure. Once complete submerged this isn't the case anymore.

  9. Mar 29, 2012 #8
    It does not have to be "in contact". The atmospheric pressure is transmitted through water. The pressure acting on the submerged body is the sum of atmospheric pressure and hydrostatic pressure. If the submerged body is flexible, the increase in atmospheric pressure may produce a change of its volume.

    The results that atmospheric pressure does not directly influence buoyancy is due to the buoyancy depending on the pressure difference (or gradient) along the vertical direction.
    Atmospheric pressure just adds a constant factor to the hydrostatic pressure and this has no contribution to the gradient.
  10. Mar 30, 2012 #9
    Correct, made a mistake there. Difference in air pressure wil result in greater hydrostatic pressure, and therefore a greater upward force.
    The object remains in static equilibrium because of difference in de weight of the air pushing downwards.

    thank for all the help
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