1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Archimedes' Principle problem help please

  1. Apr 7, 2008 #1
    1. The problem statement, all variables and given/known data
    In the figure below, a cube of edge length L = 0.500 m and mass 480 kg is suspended by a rope in an open tank of liquid of density 1030 kg/m3.
    (a) Find Ftop, the magnitude of the total downward force on the top of the cube from the liquid and the atmosphere, assuming atmospheric pressure is 1.00 atm.
    correct check mark 2.59E4N

    (b) Find Fbottom, the magnitude of the total upward force on the bottom of the cube.
    wrong check mark N

    (c) Find T, the tension in the rope.
    N

    (d) Calculate Fbu, the magnitude of the buoyant force on the cube using Archimedes' principle.
    correct check mark 1.26E3N
    What relation exists among all these quantities? (Select all that apply.)
    Fbu = Fbottom + T
    Fbu = m - T
    Fbu = Ftop - Fbottom
    Fbu = Fbottom - Ftop
    Fbu = T - m

    wrong check mark

    hint:Force is equal to the product of the (uniform) pressure and the face area. The gauge pressure at a certain depth h in a fluid is equal to ρgh. The gravitational force and the force from the rope also act on the cube. By Newton's second law, the net force must be zero.
    Section 14-7 Archimedes' Principle
    [​IMG]


    2. Relevant equations
    Fb=pVg
    F=ma


    3. The attempt at a solution
    I have no idea what to do for part b
    at first I thought Fbottom was the same as the buoyancy force but that was wrong.
    All I need is a hint on how to start part b and then I should be able to get part c on my own. I have already solved for parts A and D
     
    Last edited: Apr 7, 2008
  2. jcsd
  3. Apr 7, 2008 #2
    Think about what caused the force on the top in part A. It is the same type of force on the bottom.
     
  4. Apr 7, 2008 #3
    A(Po+pg(3/2)L)=2.71E4N
    thanks
     
  5. Apr 7, 2008 #4
    would T=Ftop+mg-Fb-Fbottom ?
     
  6. Nov 24, 2008 #5
    Can someone help me solve A and B for this problem..?

    A(Po+pg(3/2)L)=2.71E4N

    what does Po and pg mean in here?
    is A = 1.5 in this problem?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Archimedes' Principle problem help please
Loading...