A closed cubical box made of aluminum sheet floats in water with (1/4) of the volume above water. Determine the thickness of the sheet.(adsbygoogle = window.adsbygoogle || []).push({});

I first found out what the density would need to be for this orientation:

75% below water or

X % = density of box/ density of water

.75 = p/(1000)

p = 750 kg/m^3 --> effective density.

p = M(sheet) / Volume(box)

Mass of the sheet is then = 6p(s^2)x

where s is the length of a side of the cube, x is the thickness of the sheet and p is the density of aluminum (2700 kg/m^3)

M = 16200 x(s^2)

Therefore: 750 = 16200 x(s^2) / s^3

.0463 = x/s

The problem is, there seems to be not enough information.

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# Homework Help: Archimede's Principle Problem

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