- #1

physics kiddy

- 135

- 1

A block of wood of length 40 cm and area of cross-section 15 cm

^{2}floats in water with 3/8 of it's length above water. What is the density of wood ? (Density of water - 1g/cm

^{3}).

My attempt to get the solution :

Length of wood above water = 3/8 * 40 = 15cm

Length of wood below water = (40-15)cm = 25cm

Now, Upthrust = 375cm

^{3}*1*10 = 3750 N

Rest, I don't know !

Please help. It's urgent because I am going to face some deadly questions the day after tomorrow. Thank You.