# Archimedes Principle

1. Jan 17, 2016

### Nanu Nana

. The problem statement, all variables and given/known data
A block oak weighs 90 N in air. A piece of lead weighs 130 N in water. The two weigh together 100N in water. Calculate the relative density of the wood.

2. Relevant equations
F=mxg
F(archimedes)= density x Volume x g

3. The attempt at a solution
F (g)oak = 90 N
F= mxg
m= 90N/9.81 m/s2
m= 9.17 gram
Oak in water = 130-100 N =30 N
Farchimedes oak = 90N-30N =60N
60N =1000kg/m3 x V x 9.81 m/s2
V=60N/9810
V=0.00611
Now that I have calculated V I can find density
rho = 9.17kg/ 0.00611 m3
density = 1499
Relative density is 1499 /1000 kg/m3 = 1.499
But the correct answer is 0.75

Last edited by a moderator: Jan 17, 2016
2. Jan 17, 2016

### haruspex

3. Jan 17, 2016

### Nanu Nana

How to do find N Force of oak in water ??

4. Jan 17, 2016

### haruspex

Your method was ok but you made a mistake with the signs. Manipulate the two equations I wrote above.

5. Jan 17, 2016

### Nanu Nana

100+130?

6. Jan 17, 2016

### haruspex

If Ow+Lw=100 and Lw=130, what is Ow?

7. Jan 17, 2016

### Nanu Nana

Sorry /D its -30 so 90-(-30) = 120

8. Jan 17, 2016

### haruspex

Right. Does this get you to the right answer?
(How do you interpret the weight of -30N?)

9. Jan 17, 2016

### Nanu Nana

Yes I just calculated it. Negative force means opposite direction . But i don't know in this context

10. Jan 17, 2016

### haruspex

If the wood were immersed in the water without being bound to the lead, what would happen?

11. Jan 17, 2016

### Nanu Nana

It floats ofcourse

12. Jan 17, 2016

### haruspex

Right, hence the negative net force.

13. Jan 17, 2016

### Nanu Nana

Oh I see . thank you very much :)