- #1

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-an iron (7800kg/m

^{3}) body is submerged into in water (density = 1000kg/m

^{3})

his weight in the air is 0,13N.

what i did is:

E=dVg (Push force, density of the liquid, volume of the body sumerged and gravity, respectively)

then:

the volume of the iron body is 0,000633m

^{3}, then:

E = 1000*0,000633g = 1,60

so, the the apparent weight is 0,13-1,60=

**-1,47N**

______________________________

did I do it right?