1. The problem statement, all variables and given/known data A rod 6 meters in length has specific gravity 25/36. One end of the rod is tied to a 5 meter rope, which in turn is attached to the floor of a pool 10 meters deep. Find the length of the part of rod, which is out of water. The answer is 1 meter. 2. Relevant equations mg=V(imm)p(l)g=V(rod)p(rod)g F(of buoyancy)=Tension + mg 3. The attempt at a solution I don't really know what to do, but here's what I did anyway. I tried using V(imm)*density of fluid=V(rod)*density of rod. But then I thought that there should be a tension component in the force equation as well. I further tried ignoring tension, and using the above mentioned equation to figure out how much of the rod would be outside. I got 2meters. I figured I could use trig to figure out the angle of inclination with the water level, but I couldn't really use it.