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Dipra Irham

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I have got a question in my physics book.The question goes like that:

(Let's suppose the weight of the gold crown of Archimedes is 10 kg in air and 9.4 kg when immersed in water.What is the density of the crown? )

The solution says:

If the volume of the crown is V and density is p then,

Vp=10 kg

Vp-(Vp of water)=9.4 kg

Vp of water = Vp - 9.4 kg= 0.6 kg

so, V = 0.6 kg / density of water

=0.6 kg÷10^3 kg/m^3= 0.6 X 10^ -3m^3

Therefore, p = 10 kg / V

= 10 kg/0.6 X 10^ -3m^3

=16666 Kg /m^3

my question is, why Vp =10 kg?(it should be Vp times acceleration due to gravity,since weight = mass X acceleration due to gravity)

(Let's suppose the weight of the gold crown of Archimedes is 10 kg in air and 9.4 kg when immersed in water.What is the density of the crown? )

The solution says:

If the volume of the crown is V and density is p then,

Vp=10 kg

Vp-(Vp of water)=9.4 kg

Vp of water = Vp - 9.4 kg= 0.6 kg

so, V = 0.6 kg / density of water

=0.6 kg÷10^3 kg/m^3= 0.6 X 10^ -3m^3

Therefore, p = 10 kg / V

= 10 kg/0.6 X 10^ -3m^3

=16666 Kg /m^3

my question is, why Vp =10 kg?(it should be Vp times acceleration due to gravity,since weight = mass X acceleration due to gravity)