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Solve Archimedes Problem: Find Crown's Density
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[QUOTE="Mark44, post: 6007795, member: 147785"] Technically, the [U]mass[/U] of the gold crown is 10 kg in air. The crown would have the same mass on the moon with its lower gravity, but its weight would be less. The proper unit of weight in this problem would be Nt (Newtons). Immersing the crown in water wouldn't change its mass. The density here apparently is in units of ##\frac{\text{kg}}{m^3}##. Multiplying V and p results in units of kg. It's hard to tell what they're trying to say in this problem, as the units being used don't make sense. BTW, the image you posted is too small to be readable, and part of it is in shadow, which makes it even less useful. [/QUOTE]
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Solve Archimedes Problem: Find Crown's Density
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