(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

so, find the at which value does the 1/(1-6sinx) is discontinous

2. Relevant equations

3. The attempt at a solution

so, it's discontinous when the bottom is equal to zero, which is 1-6sinx=0

solve for x, which give arcsin(1/6).

and now, the correct answer is x is not = arcsin(1/6)+2pi n

and x is not = pi-arcsin(1/6)+2pi n

the bold part is where i don't understand. what? the arcsin has a period of 2pi? did we already restrict it to -pi/2 to pi/2?

what? how come the answer lays on the second quadrant? shouldn't it be lay either in first or the fourth quadraint?

what? how come the we ignore the third quadrant?

don't get it. need help

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# Homework Help: Arcsin, need help

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