(ArcSinx)^3+(ArcCosx)^3 = a

[hadi amiri 4]

(ArcSinx)^3+(ArcCosx)^3=a
discuss on a

 

[Gib Z]

$$a = \frac{ \pi ( 6 \arcsin x - 3\pi )^2}{24} + \frac{3\pi^3}{96}$$