(ArcSinx)^3+(ArcCosx)^3=a discuss on a:rolleyes:
Jun 8, 2008 #2 Gib Z Homework Helper 3,352 7 [tex] a = \frac{ \pi ( 6 \arcsin x - 3\pi )^2}{24} + \frac{3\pi^3}{96} [/tex]